The volume of ’10 vol.’ of ${{\rm{H}}_2}{{\rm{O}}_2}$ required to liberate 500 mL ${{\rm{O}}_2}$ at NTP is:

NEET UG CHEMISTRY MCQ: HYDROGEN

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Application +4 | -1

The volume of ’10 vol.’ of

{\mathrm{H}_2}{\mathrm{O}_2}

required to liberate 500 mL

{\mathrm{O}_2}

at NTP is:

View answer and explanation

Correct option: A

50 mL

Option A (50 mL) is correct because '10 vol' H2O2 means 1 mL of H2O2 gives 10 mL of O2, so to get 500 mL O2, you need 50 mL of H2O2.

Practice All Chapter MCQs →

\mathrm{CaC}_2+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Ca}(\mathrm{OH})_2+' \mathrm{X}\,'

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\mathrm{X}

\mathrm{Y}

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