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JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

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Application +4 | -1
The radical centre of the circles
x2+y2−16x+60=0,x2+y2−12x+27=0\begin{array}{l} {x^2} + {y^2} - 16x + 60 = 0,\\ {x^2} + {y^2} - 12x + 27 = 0 \end{array}
and x2+y2−12x+8=0{x^2} + {y^2} - 12x + 8 = 0 is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the calculated radical center does not match any of the given options.

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