If $0 < x < \frac{\pi }{2},$, then

$\cos \left( {\sin x} \right) = \sin \left( {\cos x} \right)$

$\cos \left( {\sin x} \right) < \sin \left( {\cos x} \right)$

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Analyzing +4 | -1

0 < x < \frac{\pi }{2},

, then

View answer and explanation

Correct option: A

\cos \left( {\sin x} \right) > \cos x

Option A (

\cos(\sin x) > \cos x

) is correct because

\cos x

is a decreasing function on

(0, \frac{\pi}{2})

and

\sin x < x

for

0 < x < \frac{\pi}{2}

Practice All Chapter MCQs →

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\triangle A B C

C

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\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=