Skip to main content
Back to FUNCTIONS

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy
1 of 1
Application +4 | -1
Let f(x)=ln⁡(x2+ax+1)f(x)=\ln \left(x^2+a x+1\right). If f(x)f(x) is defined ∀ x∈R\forall \,x \in R, then the number of integers in the range of 'aa' is:
View answer and explanation
Correct option: B
3
Option B is correct because the condition x2+ax+1>0x^2 + ax + 1 > 0 for all xx implies a2−4<0a^2 - 4 < 0, leading to 3 integers in the range of 'a'.

More Questions from FUNCTIONS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.