JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

Let

n = 2006!

Then

\frac{1}{{{{\log }_2}n}} + \frac{1}{{{{\log }_3}n}} + ... + \frac{1}{{{{\log }_{2006}}n}}

is equal to

View answer and explanation

Correct option: D

Option D (1) is correct because by using the change of base formula for logarithms and simplifying the sum, the result is 1.

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