JEE MATHEMATICS MCQ: CIRCLES

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Analyzing +4 | -1

If the point

\left( { - 5 + \frac{\lambda }{{\sqrt 2 }}, - 3 + \frac{\lambda }{{\sqrt 2 }}} \right)

is an interior point of the larger segment of the circle

{x^2} + {y^2} = 16

cut off by the line

x + y = 2,

then

View answer and explanation

Correct option: B

\lambda \in \left( {4\sqrt 2 - \sqrt {14} ,5\sqrt 2 } \right)

Option B (

\lambda \in \left( {4\sqrt 2 - \sqrt {14} ,5\sqrt 2 } \right)

) is correct because it satisfies both conditions: the point lies inside the circle and on the correct side of the line.

More Questions from CIRCLES

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{\left( {{\alpha ^2}{x^2} - 2\alpha \mathrm{ }x + 1} \right)^{51}},

x

\left( {\alpha ,2{\alpha ^2}} \right)

{x^2} + {y^2} = 4,

{x^2} + {y^2} - 2x + 4y - 4 = 0

{x^2} + {y^2} = {a^2}

\left( {{x_1},{y_1}} \right)

\quad \alpha, \beta

\gamma

P, Q

x^2+y^2=1

A

(-1,0)

A P, A Q

A R

G P

\cos \alpha / 2, \cos \beta / 2

\cos \gamma / 2

x+y=6

x+2 y=4

x+y=5

x-y=1

9 \pi