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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A body starts from rest and acquires a velocity VV in time TT. The work done on the body in time tt will be proportional to
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Correct option: D
V2T2t2\frac{V^2}{T^2} t^2
Option D (V2T2t2\frac{V^2}{T^2} t^2) is correct because work done is proportional to the square of velocity, which is proportional to the square of time.

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