JEE MATHEMATICS MCQ: FUNCTIONS

1 Medium

1 of 1

Application +4 | -1

2f\left( {x + 1} \right) + f\left( {\frac{1}{{x + 1}}} \right) = 2x\;and\;x \ne - 1

then

f\left( 2 \right)

is equal to

View answer and explanation

Correct option: C

5/3

Option C (5/3) is correct because by substituting x = 1 and x = -1/2 into the given equation, we obtain a system of two equations that can be solved for f(2).

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

, where

f(x)=x(4-x)

, then

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g(f(x))=|\sin x|

and

f(g(x))=(\sin \sqrt{x})^2

, then Let

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

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f\left( x \right) = x - \left[ x \right]

, then

{f^{ - 1}}\left( x \right)

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f: R \rightarrow R

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f(x)=x^4

, Choose the correct answer. Which of the following functions are odd functions Let

f(x)=(x+1)^2-1(x \geq-1)

. Then the set

S=\left\{x: f(x)=f^{-1}(x)\right\}

contains