JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

1 Easy

1 of 1

Application +4 | -1

The equation of the locus of all points equidistant from the point

(4,2)

and the

x

-axis, is

View answer and explanation

Correct option: B

x^{2}-8 x-4 y+20=0

Option B (

x^{2}-8 x-4 y+20=0

) is the correct equation of the locus of points equidistant from (4,2) and the x-axis.

More Questions from 2D GEOMETRY SYSTEM

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\alpha

(\alpha, 2 \alpha)

\Delta A B C

A(0,2), B(2,0)

C(4,4)

P

2 P A=3 P B

A

(0,0)

B

(4,-3)

(1, \sqrt{3}),(0,0)

(2,0)

(1,5),(-3,1) \,\&\,(-2,1)

9 x^2-16 y^2-18 x+32 y-23

=0

25 x^2+9 y^2-50 x-18 y+33=0

(0,0)(3,0)

(0,4)