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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Analyzing +4 | -1
If z2+z+1=0z^2+z+1=0, where zz is a complex number, the value of (z+1z)2+(z2+1z2)2+(z3+1z3)2+…+(z6+1z6)2\left(z+\frac{1}{z}\right)^2+\left(z^2+\frac{1}{z^2}\right)^2+\left(z^3+\frac{1}{z^3}\right)^2+\ldots+\left(z^6+\frac{1}{z^6}\right)^2 is
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Correct option: D
12
Option D (12) is correct because the sum can be simplified using the properties of complex roots of unity.

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