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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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When a motor cyclist takes a UU-turn in 4 s what is the average angular velocity of the motor cyclist.
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Correct option: A
0.7855 rads−10.7855 \mathrm{~rad} \mathrm{s}^{-1}
Option D (0.02 N.m0.02 \mathrm{~N} . \mathrm{m}) is correct because it is the result of applying the torque formula τ=MBsin⁡θ\tau = MB \sin \theta.

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