JEE MATHEMATICS MCQ: STRAIGHT LINES

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Analyzing +4 | -1

The orthocentre of the triangle with vertices

\left( {2,\frac{{\sqrt 3 - 1}}{2}} \right),\left( {\frac{1}{2}, - \frac{1}{2}} \right)

and

\left( {2, - \frac{1}{2}} \right)

View answer and explanation

Correct option: B

\left( {2, - \frac{1}{2}} \right)

Option B ((2, -

\frac{1}{2}

)) is correct because the orthocenter of a right-angled triangle is the vertex at the right angle.

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x-3 y=p, a x+2 y=q

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\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0