JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1

f\left(\frac{x-4}{x+2}\right)=2 x+1,(x \in R=\{1,-2\})

, then

\int f(x) d x

is equal to (where

C

is a constant of integration)

View answer and explanation

Correct option: B

-12 \log _e|1-x|-3 x+c

Option B (

-12 \log _e|1-x|-3 x+c

) is correct because it is the result of integrating f(x) after finding the expression for f(x) by substituting

y = \frac{x-4}{x+2}

More Questions from INDEFINITE INTEGRATION

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\int \sin ^5 x \cos ^4 x d x=

f(x)

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f\left(\frac{4}{25}\right)

\int \frac{1-7 \cos ^2 x}{\sin ^7 x \cos ^2 x} d x=\frac{f(x)}{\sin ^7 x}+C

\int {e}^{{x}^2}\left(2-\frac{1}{{x}^2}\right) {de}={e}^{{x}^2} {f}({x})+{C}

{f}\left(\frac{1}{2}\right)=2

f(1)

{C}

\int \frac{x^7}{\left(1-x^2\right)^5} d x

\int \,\frac{{a{x^3} + \,\,b{x^2} + c}}{{{x^4}}}\;\,dx