JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Application +4 | -1

\cos (\alpha+\beta)=4 / 5

and

\sin (\alpha-\beta)=5 / 13

where

0 \leq \alpha, \beta \leq \pi / 4

, then

\tan 2 \alpha=

View answer and explanation

Correct option: D

56 / 33

Option D (

56 / 33

) is correct because it is the result of applying the tangent addition formula after finding

\tan(\alpha+\beta)

and

\tan(\alpha-\beta)

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\tan \alpha=\frac{p}{q}

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\alpha

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\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

\triangle A B C

C

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=