JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

\alpha+\beta+\gamma=\pi

then the minimum value of

\cos A+\cos B+\cos C

View answer and explanation

Correct option: D

is -3

Option D (is -3) is correct because the minimum value of cosine is -1, and if A=B=C=π, then cosA+cosB+cosC = -3.

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