JEE MATHEMATICS MCQ: MEAN VALUES THEOREM

1 Easy

1 of 1

Application +4 | -1

Value of

c

in the Lagrange's mean value theorem for the function

f(x)=x+\frac{1}{x} \text { on }\left[\frac{1}{2}, 2\right\}

View answer and explanation

Correct option: C

Option C (1) is correct because it is the only value within the interval

(\frac{1}{2}, 2)

that satisfies the Lagrange's Mean Value Theorem for the given function.

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f(x)

f(x)

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f\left( x \right) = \sqrt {x - 1} + \sqrt {x + 24 - 10\sqrt {x - 1} } ,\;1 \le x \le 26

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f\left( x \right) = x\left( {x - 1} \right)\left( {x - 2} \right)