JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

{c^2} = {a^2} + {b^2},\,\,2\;s = a + b + c

, then

4s\,\,\left( {s - a} \right)\,\,\left( {s - b} \right)\,\,\left( {s - c} \right) =

View answer and explanation

Correct option: C

{c^2}\,{a^2}

Option D (

{a^2}\,{b^2}

) is correct because using the given condition

{c^2} = {a^2} + {b^2}

and the area of the triangle, we can deduce that

4s(s-a)(s-b)(s-c) = a^2b^2

More Questions from PROPERTIES OF TRIANGLES

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