When sulphur dioxide is passed in an acidified ${{\rm{K}}_2}{\rm{C}}{{\rm{r}}_2}{{\rm{O}}_7}$ solution, the oxidation state of sulphur is changed from

NEET UG CHEMISTRY MCQ: REDOX REACTIONS

1 Medium

1 of 1

Application +4 | -1

When sulphur dioxide is passed in an acidified

{\mathrm{K}_2}\mathrm{C}{\mathrm{r}_2}{\mathrm{O}_7}

solution, the oxidation state of sulphur is changed from

View answer and explanation

Correct option: C

4 to 6

Option C (4 to 6) is correct because sulphur dioxide (

\mathrm{SO}_2

) is oxidized to sulphate (

\mathrm{SO}_4^{2-}

), changing the oxidation state of sulphur from +4 to +6.

Practice All Chapter MCQs →

{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }