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JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Application +4 | -1
The order and degree of the differential equation (1+(dydx)2)34=(d2ydx2)13{\left( {1 + {{\left( {\frac{{dy}}{{dx}}} \right)}^2}} \right)^{\frac{3}{4}}} = {\left( {\frac{{{d^2}y}}{{d{x^2}}}} \right)^{\frac{1}{3}}} is
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Correct option: A
(2,4)\left( {2,4} \right)
Option A ((2,4)) is correct because after eliminating the fractional powers, the highest order derivative is 2 and its power is 4.

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