If $x = A\cos 4t + B\sin 4t,$ then $\frac{{{d^2}x}}{{d{t^2}}}$ is equal to

JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Application +4 | -1

x = A\cos 4t + B\sin 4t,

then

\frac{{{d^2}x}}{{d{t^2}}}

is equal to

View answer and explanation

Correct option: A

- 16x

Option A (

- 16x

) is correct because it is the second derivative of the given function, obtained by differentiating twice with respect to t.

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