JEE MATHEMATICS MCQ: CIRCLES

1 Easy

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Application +4 | -1

If the circles

{\left( {x - a} \right)^2} + {\left( {y - b} \right)^2} = {c^2}

and

{\left( {x - b} \right)^2} + {\left( {y - a} \right)^2} = {c^2}

touch each other, then

View answer and explanation

Correct option: B

a = b \pm \sqrt 2 c

Option B (

a = b \pm \sqrt 2 c

) is correct because the condition for the circles to touch leads to this relationship between a, b, and c.

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\gamma

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9 \pi