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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy
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Application +4 | -1
Suppose α,β>0\alpha, \beta>0 and α+2β=π/2\alpha+2 \beta=\pi / 2, then tan⁡(α+β)−2tan⁡α−tan⁡β\tan (\alpha+\beta)-2 \tan \alpha-\tan \beta is equal to:
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Correct option: A
0
Option A (0) is correct because using the given condition α+2β=π2\alpha + 2\beta = \frac{\pi}{2}, we can show that tan⁡(α+β)−2tan⁡α−tan⁡β=0\tan (\alpha+\beta)-2 \tan \alpha-\tan \beta = 0.

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