If ${e^x} = y + \sqrt {1 + {y^2}} ,$ then the value of $y$ is

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

{e^x} = y + \sqrt {1 + {y^2}} ,

then the value of

y

View answer and explanation

Correct option: B

\frac{1}{2}\left( {{e^x} - {e^{ - x}}} \right)

Option B is correct because solving the equation for y involves algebraic manipulation and recognizing the hyperbolic sine function.

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