JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

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Application +4 | -1

The solution of

y^{\prime}+\cos (x+y)=\cos (x-y)

and

y\left(\frac{\pi}{4}\right)=\frac{\pi}{4}

is given by

View answer and explanation

Correct option: B

\cos y=2 \sin x \sin ^2 y

Option B (

\cos y=2 \sin x \sin ^2 y

) is correct because it is the solution to the differential equation

y^{\prime}+\cos (x+y)=\cos (x-y)

with the initial condition

y(\frac{\pi}{4})=\frac{\pi}{4}

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