A body cools from $75^{\circ} \mathrm{C}$ to $72^{\circ} \mathrm{C}$ in time $t_1$ from $72^{\circ} \mathrm{C}$ to $69^{\circ} \mathrm{C}$ in $t_2$ and from $69^{\circ} \mathrm{C}$ to $66^{\circ} \mathrm{C}$ in ${t}_3$, then

JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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A body cools from

75^{\circ} \mathrm{C}

72^{\circ} \mathrm{C}

in time

t_1

from

72^{\circ} \mathrm{C}

69^{\circ} \mathrm{C}

t_2

and from

69^{\circ} \mathrm{C}

66^{\circ} \mathrm{C}

{t}_3

, then

View answer and explanation

Correct option: A

t_3>t_2>t_1

Option A (

t_3>t_2>t_1

) is correct because, according to Newton's law of cooling, the rate of cooling decreases as the temperature difference between the body and surroundings decreases.

JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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