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JEE PHYSICS MCQ: OSCILLATIONS

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Analyzing +4 | -1
Two simple harmonic motions are represented by the equations
x1=5sin⁡(2πt+π4),x2=52(sin⁡2πt+cos⁡2πt).x_1=5 \sin \left(2 \pi t+\frac{\pi}{4}\right), x_2=5 \sqrt{2}(\sin 2 \pi t+\cos 2 \pi t) .
The ratio of amplitudes of x1x_1 and x2x_2 is
View answer and explanation
Correct option: C
1:21: 2
Option C (1:21: 2) is correct. The amplitude of x1x_1 is 5, and the amplitude of x2x_2 is 10, so the ratio is 1:2.

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