JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

If the centre and radius of the circle

\left|\frac{z-2}{z-3}\right|=2

are respectively

(\alpha, \beta)

and

\gamma

, then

3(\alpha+\beta+\gamma)

is equal to

View answer and explanation

Correct option: B

The correct answer is B (12) because the value of

3(\alpha+\beta+\gamma)

is calculated correctly based on the center and radius of the given circle.

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