When 1 F of electricity is passed through acidulated water, ${{\rm{O}}_2}$ evolved is

$5.6{\kern 1pt} {\kern 1pt} {\rm{d}}{\kern 1pt} {{\rm{m}}^3}$

$1.0{\kern 1pt} {\kern 1pt} {\rm{d}}{\kern 1pt} {{\rm{m}}^3}$

$11.2{\kern 1pt} {\kern 1pt} {\rm{d}}{\kern 1pt} {{\rm{m}}^3}$

$22.4{\kern 1pt} {\kern 1pt} {\rm{d}}{\kern 1pt} {{\rm{m}}^3}$

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

1 Medium

1 of 1

Application +4 | -1

When 1 F of electricity is passed through acidulated water,

{\mathrm{O}_2}

evolved is

View answer and explanation

Correct option: B

5.6{\kern 1pt} {\kern 1pt} \mathrm{d}{\kern 1pt} {\mathrm{m}^3}

Option B (

5.6{\kern 1pt} {\kern 1pt} \mathrm{d}{\kern 1pt} {\mathrm{m}^3}

) is correct because 1 F of electricity passed through acidulated water evolves 0.25 moles of

O_2

, which occupies 5.6 L (or

5.6{\kern 1pt} {\kern 1pt} \mathrm{d}{\kern 1pt} {\mathrm{m}^3}

) at STP.