If area of triangle with vertices (0, 0), (0, 6) and $\left( {{\rm{\alpha }},{\rm{\;\beta }}} \right)$ is 15 sq unit, then

${\rm{\alpha }} = \pm 5,{\rm{\;\beta \;}}$ can take any real value

${\rm{\alpha }} = \pm 5,{\rm{\;\beta }} = 5$

${\rm{\alpha }} = \pm 10,{\rm{\;\beta }} = 5$

${\rm{\alpha }} = \pm 5,{\rm{\;\beta }} = 2$

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JEE MATHEMATICS MCQ: STRAIGHT LINES

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If area of triangle with vertices (0, 0), (0, 6) and

\left( {\mathrm{\alpha },\mathrm{\;\beta }} \right)

is 15 sq unit, then

View answer and explanation

Correct option: D

\mathrm{\alpha } = \pm 5,\mathrm{\;\beta \;}

can take any real value

Option D (

\alpha = \pm 5

\beta

can take any real value) is correct because the area of the triangle depends only on the x-coordinate of the third vertex, and the y-coordinate can be any real number.

JEE MATHEMATICS MCQ: STRAIGHT LINES

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