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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫sin⁡θ+cos⁡θ(sin⁡2θ)dθ\int {\frac{{\sin \theta + \cos \theta }}{{\sqrt {\left( {\sin 2\theta } \right)} }}d\theta } is equal to
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Correct option: B
sin⁡−1θ(sin⁡θ−cos⁡θ){\sin ^{ - 1}}\theta \left( {\sin \theta - \cos \theta } \right)
Option C (sin⁡−1(cos⁡θ−sin⁡θ){\sin ^{ - 1}}\left( {\cos \theta - \sin \theta } \right)) is incorrect. Option B (sin⁡−1(sin⁡θ−cos⁡θ){\sin ^{ - 1}}\left( {\sin \theta - \cos \theta } \right)) is correct because after substituting t=sin⁡θ−cos⁡θt = \sin \theta - \cos \theta, the integral simplifies to arcsin(t).

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