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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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The value of ∫0π/2  cos⁡  θ4  −  sin⁡2  θ  dθ\int \nolimits_0^{\mathrm{\pi }/2} \,\,\frac{{\cos \,\,\mathrm{\theta }}}{{\sqrt {4\,\, - \,\,{{\sin }^2}\,\,\mathrm{\theta }} }}\,\,d\mathrm{\theta } is
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Correct option: B
π6\frac{\mathrm{\pi }}{6}
Option B (π6\frac{\mathrm{\pi }}{6}) is correct because after substitution, the integral becomes a standard arcsin integral, evaluating to π6\frac{\pi}{6}.

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