JEE MATHEMATICS MCQ: MATHEMATICAL REASONING

1 Easy

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Analyzing +4 | -1

The proposition

\left( {p \to \sim p} \right) \wedge \left( { \sim p \to p} \right)

is a

View answer and explanation

Correct option: B

Contradiction

Option B (Contradiction) is correct because the given proposition simplifies to

p \wedge \sim p

, which is always false.

More Questions from MATHEMATICAL REASONING

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p:A

q:A

\sqrt{3}

p

q

p \rightarrow q

{F_1}(A,\,B,\,C) = \left( {A \wedge \sim B} \right) \vee \left[ { \sim C \wedge \left( {A \vee B} \right)} \right] \vee \sim A

{F_2}(A,\,B) = \left( {A \vee B} \right) \vee (B \to \, \sim \,A)

p

n

q:

n

p \Leftrightarrow q