JEE MATHEMATICS MCQ: MATHEMATICAL REASONING

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Analyzing +4 | -1

Let

{F_1}(A,\,B,\,C) = \left( {A \wedge \sim B} \right) \vee \left[ { \sim C \wedge \left( {A \vee B} \right)} \right] \vee \sim A

and

{F_2}(A,\,B) = \left( {A \vee B} \right) \vee (B \to \, \sim \,A)

be two logical expressions. Then,

View answer and explanation

Correct option: C

{F_1}

is not tautology but

{F_2}

is a tautology

Option C (

{F_1}

is not tautology but

{F_2}

is a tautology) is correct because F1 can be false for some truth values of A, B, and C, while F2 is always true.

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