Mark out the enthalphy of formation of carbon monoxide (CO)Given,${\rm{C}}\left( s \right) + {{\rm{O}}_2}\left( {\rm{g}} \right) \to {\rm{CO}}\left( {\rm{g}} \right)\;,\Delta H = - 393.3\;kJ/mol$ ${\rm{CO}}\left( {\rm{g}} \right) + \frac{1}{2}{{\rm{O}}_2}\left( {\rm{g}} \right) \to {\rm{C}}{{\rm{O}}_2}\left( {\rm{g}} \right),\Delta H = - 282.8{\rm{kJ}}/{\rm{mol}}$

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Mark out the enthalphy of formation of carbon monoxide (CO)Given,

\mathrm{C}\left( s \right) + {\mathrm{O}_2}\left( \mathrm{g} \right) \to \mathrm{CO}\left( \mathrm{g} \right)\;,\Delta H = - 393.3\;kJ/mol

\mathrm{CO}\left( \mathrm{g} \right) + \frac{1}{2}{\mathrm{O}_2}\left( \mathrm{g} \right) \to \mathrm{C}{\mathrm{O}_2}\left( \mathrm{g} \right),\Delta H = - 282.8\mathrm{kJ}/\mathrm{mol}

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Correct option: A

110.5 kJ/mol

Option A (110.5 kJ/mol) is correct because the enthalpy of formation of CO is calculated by subtracting the enthalpy of the second reaction from the first reaction.

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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