JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

(3+i)(z+\bar{z})-(2+i)(z-\bar{z})+14 i=0

, where

i=\sqrt{-1}

, then

z \bar{z}

is equal to

View answer and explanation

Correct option: A

Option A (10) is correct because by substituting z = x + iy into the given equation and solving for x and y, we find that

z\bar{z} = x^2 + y^2 = 10

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