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JEE MATHEMATICS MCQ: MATHEMATICAL REASONING

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Analyzing +4 | -1
If the truth value of the statement (P∧(∼R))→(P \wedge(\sim R)) \rightarrow ((∼R)∧Q)((\sim R) \wedge Q) is FF, then the truth value of which of the following is FF ?
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Correct option: D
∼(R∨Q)→∼P\sim(R \vee Q) \rightarrow \sim P
Option D (∼(R∨Q)→∼P\sim(R \vee Q) \rightarrow \sim P) is correct because when the given statement is false, P is true, R is false, and Q is false, making this option also false.

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