JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

The real part of

{\left( {1 - \cos \theta + 2i\sin \theta } \right)^{ - 1}}

View answer and explanation

Correct option: D

\frac{1}{{5 + 3\cos \theta }}

Option D (

\frac{1}{{5 + 3\cos \theta }}

) is correct because it is the real part of the given complex expression after rationalizing the denominator.

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\left|\sum\limits_{r=1}^n z_r\right|

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\alpha, \beta

\gamma

|\alpha-\beta|

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