JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Analyzing +4 | -1

P

is a point on the altitude

A D

of the

\triangle A B C

such that

\angle C D P=\frac{B}{3}

, then

A P

is equal to

View answer and explanation

Correct option: C

2 c \sin \frac{B}{3}

Option C (

2 c \sin \frac{B}{3}

) is correct because by applying the sine rule in triangle ABP, AP can be expressed as

2 c \sin \frac{B}{3}

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