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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1
A stone of mass 1 kg tied to the end of a string of length 1 m, is whirled in a horizontal circle with a uniform angular velocity 2 rads−1\mathrm{rad}{\mathrm{s}^{ - 1}}. The tension of the string is (in newton)
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Correct option: C
4
The correct answer is 4 because the tension in the string is equal to the centripetal force, which can be calculated using the given mass, radius, and angular velocity.

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