JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

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Analyzing +4 | -1

The two circles

{x^2} + {y^2} - 2x - 2y - 7 = 0

and

3\left( {{x^2} + {y^2}} \right) - 8x + 29y = 0

View answer and explanation

Correct option: C

Cut each other orthogonally

Option C (Cut each other orthogonally) is correct because the condition

2(g_1g_2 + f_1f_2) = c_1 + c_2

is satisfied, indicating that the circles intersect at right angles.

More Questions from SYSTEM OF CIRCLES

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x = 1

{x^2} + {y^2} = 4

{x^2} + {y^2} + 8y - 4 = 0

{x^2} + {y^2} + gx + 4 = 0

x^2+y^2+3 x+2 y+1=0

x^2+y^2+3 x+4 y+2=0

{x^2} + {y^2} + 2ky + 2x + 6 = 0

{x^2} + {y^2} + 2ky + k = 0

k

x^2+y^2+2 a x+c y+a=0

x^2+y^2-3 a x+d y-1=0

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5 x+b y-a=0

P

Q

x + 2y - 3 = 0

{x^2} + {y^2} - 4y + 1 = 0

{x^2} + {y^2} - 4x - 2y + 4 = 0