JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

I_n=\int_0^{\frac{\pi}{4}} \tan n \theta d \theta

, then

I_{2020}+I_{2022}

View answer and explanation

Correct option: D

\frac{1}{2021}

Option D (

\frac{1}{2021}

) is correct because the recurrence relation

I_n + I_{n-2} = \frac{1}{n-1}

applies to this integral, leading to

I_{2020} + I_{2022} = \frac{1}{2021}

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