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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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If I=∫x27(6x2+5x+4)(x2+x+1)6dx=f(x)+CI=\int x^{27}\left(6 x^2+5 x+4\right)\left(x^2+x+1\right)^6 d x=f(x)+C, then f(x)f(x) is equal to
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Correct option: A
17(x6+x5+x4)7\frac{1}{7}\left(x^6+x^5+x^4\right)^7
Option D (12x2ex2ex4+C\frac{1}{2} x^2 e^{x^2} e^{x^4}+C) is correct because by using the substitution x2=tx^2=t and recognizing the pattern for integration, the integral simplifies to the given expression.

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