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JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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Application +4 | -1
When the reverse bias in a junction diode is changed from 5V to 15V, the value of current changes from 38 μA38\,\mu A to 88 μA88\,\mu A. The reverse resistance of the junction diode will be
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Correct option: B
2×105 Ω2 \times {10^5}\,\Omega
Option B (2×105 Ω2 \times {10^5}\,\Omega) is correct because it is calculated using Ohm's law for the change in voltage and current in the reverse bias.

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