JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

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Analyzing +4 | -1

\int \frac{1}{a^2 \sin ^2 x+b^2 \cos ^2 x} d x=\frac{1}{12} \tan ^{-1}(3 \tan x)+C,

then the maximum value of

a \sin x+b \cos x

, is

View answer and explanation

Correct option: B

\sqrt{40}

Option C is correct because after simplifying the integral, we find that

ab = 12

and

\frac{a}{b} = 3

, leading to the maximum value of

a \sin x + b \cos x

being

\sqrt{40}

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