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NEET UG CHEMISTRY MCQ: CHEMICAL KINETICS

1 Hard
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Application +4 | -1
Find the two third life (t1/2)\left( {{t_{1/2}}} \right) of a first order reaction in which k=5.48×10−14k = 5.48 \times {10^{ - 14}} per second
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Correct option: B
2.01×1013  s2.01 \times {10^{13}}\;s
Option B (2.01×1013  s2.01 \times {10^{13}}\;s) is correct because it is the calculated two-thirds life of a first-order reaction using the given rate constant.

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