JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

Angles

A,B

and

C

of a

\Delta \;ABC

are in AP. If

\frac{b}{c} = \frac{{\sqrt 3 }}{{\sqrt 2 }}

, then angle

A

is equal to

View answer and explanation

Correct option: C

\frac{{5\pi }}{{12}}

Option C (

\frac{{5\pi }}{{12}}

) is correct because by using the sine rule and the given ratio of sides, we can find angle A to be 75 degrees, which is

\frac{{5\pi }}{{12}}

radians.

More Questions from PROPERTIES OF TRIANGLES

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{p_1},{p_2},{p_3}

\Delta \;ABC

A,B,C

\Delta

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

5k,\;6k,\;5k

k

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

2 s