$\smallint \,\,x{e^{{x^2}}}\,\,dx$ is equal to

$\frac{{{e^x}}}{2}\,\, + \,\,c$

$ - \,\,\frac{{{e^x}}}{2}\,\, + \,\,c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \,\,x{e^{{x^2}}}\,\,dx

is equal to

View answer and explanation

Correct option: B

\frac{{{e^{{x^2}}}}}{2}\,\, + \,\,c

Option B is correct because by substituting x² = t, the integral is simplified and evaluated to be e^(x²)/2 + c.

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