NEET UG CHEMISTRY MCQ: Equilibrium

1 Hard

1 of 1

Analyzing +4 | -1

A solution is 0.1 M in

C{l^ - }

and 0.001 M in

CrO_4^{2 - }

. Solid

AgN{O_3}

is gradually added to it. Assuming that the addition does not change in volume and

{K_{sp}}(AgCl) = 1.7 \times {10^{ - 10}}\,{M^2}

and

{K_{sp}}(A{g_2}Cr{O_4}) = 1.9 \times {10^{ - 12}}\,{M^3}

Select correct statement from the following

View answer and explanation

Correct option: D

AgCl

will precipitate first as the amount of

A{g^ + }

needed to precipitate is low.

Option D (

AgCl

will precipitate first as the amount of

A{g^ + }

needed to precipitate is low) is correct because it requires a lower concentration of

Ag^+

to reach the

K_{sp}

for

AgCl

compared to

Ag_2CrO_4

More Questions from Equilibrium

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Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}