NEET UG PHYSICS MCQ: MOTION IN PLANE

1 Easy

1 of 1

Analyzing +4 | -1

Assertion If a particle is projected vertically upwards with velocity

u

, the maximum height attained by the particle is

h_1

. The same particle is projected at angle

30^{\circ}

from horizontal with the same speed

u

. Now the maximum height is

h_2

. Thus,

h_1=4 h_2

.

Reason In first case,

v=0

at highest point and in second case,

v \neq 0

at highest point.

View answer and explanation

Correct option: B

If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.

Option B (If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion) is correct. The assertion is correct because

h_1 = u^2/2g

and

h_2 = (u \sin 30)^2/2g = u^2/8g

, thus

h_1 = 4h_2

. The reason is also correct, but it doesn't explain the relationship between

h_1

and

h_2

More Questions from MOTION IN PLANE

Practice All Chapter MCQs →

Acceleration due to gravity: The magnitudes of the two vectors

\mathrm{\vec a}\,and\,\mathrm{\vec b}

are a and b respectively. The vector product of

\mathrm{\vec a}\,and\,\mathrm{\vec b}

cannot be If

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

, then the angle between

\overrightarrow Q \,and\,\overrightarrow R

is What happens, when we multiply a vector by -2 ? Which of the following is not true? If

\vec{A}=3 \hat{i}+4 \hat{j}

and

\vec{B}=6 \hat{i}+8 \hat{j}

where

A

and

B

are the magnitudes of

\overrightarrow{\mathrm{A}}

and

\overrightarrow{\mathrm{B}}

The wind appears to blow from the north to a man moving in the north-east direction. When he doubles his velocity the wind appears to move in the direction

{\cot ^{ - 1}}\left( 2 \right)

east of north. The actual direction of the wind is