Following forces start acting on a particle at rest at the origin of the co-ordinate system simultaneously ${{\rm{\vec F}}_1} = 5\hat i - 5\hat j + 5\hat k,{\rm{\;\;\;}}{{\rm{F}}_2} = 2\hat i + 8\hat j + 6\hat k,{{\rm{F}}_3} = - 6\hat i + 4\hat j - 7\hat k,{{\rm{F}}_4} = - \hat i - 3\hat j - 2\hat k.$ The particle will move

JEE PHYSICS MCQ: MOTION IN PLANE

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Following forces start acting on a particle at rest at the origin of the co-ordinate system simultaneously

{\mathrm{\vec F}_1} = 5\hat i - 5\hat j + 5\hat k,\mathrm{\;\;\;}{\mathrm{F}_2} = 2\hat i + 8\hat j + 6\hat k,{\mathrm{F}_3} = - 6\hat i + 4\hat j - 7\hat k,{\mathrm{F}_4} = - \hat i - 3\hat j - 2\hat k.

The particle will move

View answer and explanation

Correct option: B

in y-z plane

Option B (in y-z plane) is correct because the resultant force vector has no component along the y-axis, indicating motion in the y-z plane.

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\mathrm{\vec P} = \mathrm{\vec A} + \mathrm{\vec B}\,\,\mathrm{and}\,P = A + B.

\mathrm{\vec A}\,and\,\mathrm{\vec B}

0^{\circ}

90^{\circ}

\mathrm{If}\,(\mathbf{a}+3 \mathbf{b}) \cdot(7 \mathbf{a}-5 \mathbf{b})=0

(\mathbf{a}-4 \mathbf{b}) \cdot(7 \mathbf{a}-2 \mathbf{b})=0

\mathbf{a}

\mathbf{b}

\theta

\left(90^{\circ}-\theta\right)

39.2 \mathrm{~ms}^{-1}

50 \mathrm{~m}

{g}=9.8 \mathrm{~ms}^{-2}